cs-3333: add hw 5
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Fall-2024/CS-3333/Assignments/5/Assignment.typ
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567
Fall-2024/CS-3333/Assignments/5/Assignment.typ
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#show link: set text(blue)
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#set text(font: "Calibri")
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#show raw: set text(font: "Fira Code")
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#set table.cell(breakable: false)
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#set table(stroke: (x, y) => (
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left: if x > 0 {
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.1pt
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},
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top: if y == 1 {
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0.5pt
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} else if y > 1 {
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0.1pt
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},
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))
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#set math.mat(delim: "[")
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#set page("us-letter")
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#let solve(solution) = {
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block(
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inset: 5pt,
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stroke: blue + .3pt,
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fill: rgb(0, 149, 255, 15%),
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radius: 4pt,
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)[#solution]
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}
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#let solvein(solution) = {
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let outset = 3pt
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h(outset)
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box(
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outset: outset,
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stroke: blue + .3pt,
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fill: rgb(0, 149, 255, 15%),
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radius: 4pt,
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)[#solution]
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}
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#let note(content) = {
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block(
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inset: (left: 5pt, right: 5pt, top: 10pt, bottom: 10pt),
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stroke: luma(20%) + .3pt,
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fill: luma(95%),
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radius: 4pt,
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)[#content]
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}
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#let notein(content) = {
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let outset = 3pt
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h(outset)
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box(
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outset: outset,
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stroke: luma(20%) + .3pt,
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fill: luma(95%),
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radius: 4pt,
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)[#content]
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}
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#align(center)[
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= CS 3333 Mathematical Foundations
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Homework 5 (100 pts)\
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#underline[Price Hiller] | #underline[zfp106]
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]
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#line(length: 100%, stroke: .25pt)
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*Questions*\
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Please write down the major intermediate steps.
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1. Calculate the rank of the following matrices. (12 pts)
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#grid(
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columns: 2,
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align: center,
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gutter: 2em,
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[
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$A = mat(
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2, -1, 3;
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1, 0, 1;
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0, 2, -1;
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1, 1, 4;
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)$
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],
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[
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(6 pts)
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],
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grid.cell(
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colspan: 2,
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[
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#note[
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#grid(
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column-gutter: (1em, 4em, 1em, 1em),
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columns: 2,
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align: left + horizon,
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row-gutter: 2em,
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[$R_4 = R_4 - R_2$],
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[$mat(
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2, -1, 3;
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1, 0, 1;
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0, 2, -1;
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0, 1, 3;
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)$],
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[$R_1 = 1 / 2 R_1$],
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[$mat(
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1, -1/2, 3/2;
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1, 0, 1;
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0, 2, -1;
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0, 1, 3;
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)$],
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[$R_2 = R_2 - R_1$],
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[$mat(
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1, -1/2, 3/2;
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0, 1/2, -1/2;
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0, 2, -1;
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0, 1, 3;
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)$],
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[$R_2 = 2R_2$],
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[$mat(
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1, -1/2, 3/2;
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0, 1, -1;
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0, 2, -1;
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0, 1, 3;
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)$],
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[$R_4 = R_4 - R_2$],
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[$mat(
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1, -1/2, 3/2;
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0, 1, -1;
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0, 2, -1;
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0, 0, 4;
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)$],
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[$R_3 = R_3 - 2R_2$],
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[$mat(
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1, -1/2, 3/2;
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0, 1, -1;
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0, 0, 1;
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0, 0, 4;
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)$],
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[$R_4 = R_4 - 3R_3$],
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[$mat(
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1, -1/2, 3/2;
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0, 1, -1;
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0, 0, 1;
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0, 0, 0;
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)$],
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grid.cell(colspan: 2, align: center, solve[The rank of $A$ is 3.])
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)
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]
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],
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),
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colbreak(),
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colbreak(),
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[
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$B = mat(
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3, 2, -1;
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2, -3, -5;
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-1, -4, -3;
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)$
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],
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[
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(6 pts)
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],
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grid.cell(
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colspan: 2,
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[
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#note[
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#grid(
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column-gutter: (1em, 4em, 1em, 1em),
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columns: 2,
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align: left + horizon,
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row-gutter: 2em,
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[$R_2 = R_2 + 2R_4$],
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[$mat(
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3, 2, -1;
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0, -11, -11;
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-1, -4, -3;
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)$],
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[$R_2 = -1 / 11 R_2$],
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[$mat(
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3, 2, -1;
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0, 1, 1;
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-1, -4, -3;
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)$],
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[$R_4 ↔ R_2$],
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[$mat(
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3, 2, -1;
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-1, -4, -3;
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0, 1, 1;
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)$],
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[$R_2 = R_2 + 1 / 3R_1$],
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[$mat(
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3, 2, -1;
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0, -10/3, 10/3;
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0, 1, 1;
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)$],
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[$R_2 = -3 / 10 R_2$],
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[$mat(
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3, 2, -1;
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0, 1, 1;
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0, 1, 1;
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)$],
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[$R_3 = R_3 - R_2$],
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[$mat(
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3, 2, -1;
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0, 1, 1;
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0, 0, 0;
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)$],
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grid.cell(colspan: 2, align: center, solve[The rank of $B$ is 2.])
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)
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]
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],
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),
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)
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2. Solve the following systems using the inverse of a matrix. (12 pts)
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#grid(
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columns: 2,
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align: center,
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gutter: 2em,
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[
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$
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-7x + 3y &= -34\
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8x -4y &= 44
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$
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],
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[
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(4 pts)
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],
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grid.cell(
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colspan: 2,
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[
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#note[
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#columns(2)[
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$
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cases(
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-7x + 3y = -34\
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8x -4y = 44
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) -> mat( -7, 3, -34; 8, -4, 44; augment: #2)\
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$
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$
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R_1 &= -1 / 7 R_1& &-> mat( 1, -3/7, -34/7; 8, -4, 44; augment: #2)\
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R_2 &= R_2 - 8R_1& &-> mat( 1, -3/7, -34/7; 0, -4/7, 36/7; augment: #2)\
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R_2 &= -7 / 4R_2& &-> mat( 1, -3/7, -34/7; 0, 1, -9; augment: #2)\
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R_1 &= R_1 + 3 / 7R_2& &-> mat(1, 0, 1; 0, 1, -9; augment: #2)\
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$
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#solve[$x = 1, y = -9$]
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]
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]
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],
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),
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[
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$
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5x + 15y + 56z &= 35\
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-4x - 11y -41z &= -26\
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-x - 3y - 11z &= -7
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$
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],
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[
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(8 pts)
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],
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grid.cell(
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colspan: 2,
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[
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#note[
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#block(inset: (left: 30pt, right: 30pt))[
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$
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cases(
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5x + 15y + 56z& =& 35\
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-4x - 11y -41z& =& -26\
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-x - 3y - 11z& =& -7
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) -> mat(5, 15, 56, 35; -4,-11,-41,-26;-1,-3,-11,-7; augment: #3)\
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$
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$
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R_1 &= 1 / 5 R_1& &-> mat(1, 3, 56/5, 7; -4,-11,-41,-26;-1,-3,-11,-7; augment: #3)\
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R_2 &= R_2 + 4R_1& &-> mat(1, 3, 56/5, 7; 0, 1, 19/5, 2;-1,-3,-11,-7; augment: #3)\
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R_3 &= R_3 + R_1& &-> mat(1, 3, 56/5, 7; 0, 1, 19/5, 2;0,0,1/5,0; augment: #3)\
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R_1 &= R_1 - 3R_2& &-> mat(1,0,-1/5,1; 0, 1, 19/5, 2;0,0,1/5,0; augment: #3)\
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R_3 &= 5R_3& &-> mat(1,0,-1/5,1; 0, 1, 19/5, 2;0,0,1,0; augment: #3)\
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R_1 &= R_1 +1 / 5 R_3& &-> mat(1,0,0,1; 0, 1, 19/5, 2;0,0,1,0; augment: #3)\
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R_2 &= R_2 - 19 / 5 R_3& &-> mat(1,0,0,1; 0, 1, 0, 2;0,0,1,0; augment: #3)\
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$
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#solve[$x = 1, y = 2, z=0$]
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]
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]
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],
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),
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)
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#align(center + bottom, note[#text(size: 3em)[⇊ SEE NEXT PAGE ⇊]])
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#pagebreak()
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3. Find the eigenvalues and eigenvectors of the following matrices. (12 pts)
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#grid(
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columns: 2,
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align: center,
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gutter: 2em,
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[
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$A = mat(
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2, 3;
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-3, -5;
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)$
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],
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[
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(4 pts)
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],
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grid.cell(
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colspan: 2,
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[
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#note[
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#block(inset: (left: 30pt, right: 30pt))[
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#underline[Calculating Eigenvalues]
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$
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A - λ ⋅"I" &= mat(2 - λ, 3;-3, -5 - λ)&\
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mat(delim: "|", 2 - λ, 3;-3, -5 - λ) &= 0&\
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(2 - λ)(-5-λ) - 3(-3) &=0&\
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(2 - λ)(-5-λ) + 9 &=0&\
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(-3 + sqrt(13)) / 2,(-3 - sqrt(13)) / 2&= λ&\
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$
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#underline[Calculating Eigenvectors]
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#solve[
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Eigen Values: $(-3 + sqrt(13)) / 2,(-3 - sqrt(13)) / 2$
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]
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]
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]
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#align(left)[#text(
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red,
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weight: "black",
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)[And it is at this point that I have run out of time :(. I forgot this was due tonight, I thought today was the 13th until I saw that football was on at 9pm. My stomach dropped a few miles as you might imagine. At this point, I've winged it and scraped what I could together. May the dice roll in my favor.]]
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],
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),
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[
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$B = mat(
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2, 0, 0;
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0, 4, 5;
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0, 4, 3;
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)$
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],
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[
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(8 pts)
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],
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grid.cell(colspan: 2, []),
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)
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4. List all the permutations of ${P,Q, R, S}$ (6 pts).
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#solve[
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#grid(
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align: center,
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columns: 4,
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[
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${P,Q,R,S}$
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${P,Q,S,R}$
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${P,R,Q,S}$
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${P,R,S,Q}$
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${P,S,Q,R}$
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${P,S,R,Q}$
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],
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[
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${Q,P,R,S}$
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${Q,P,S,R}$
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${Q,R,P,S}$
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${Q,R,S,P}$
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${Q,S,P,R}$
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${Q,S,R,P}$
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],
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[
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${R,P,Q,S}$
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${R,P,S,Q}$
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${R,Q,P,S}$
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${R,Q,S,P}$
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${R,S,P,Q}$
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${R,S,Q,P}$
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],
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[
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${S,P,Q,R}$
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${S,P,R,Q}$
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${S,Q,P,R}$
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${S,Q,R,P}$
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${S,R,P,Q}$
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${S,R,Q,P}$
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],
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)]
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#align(center + bottom, note[#text(size: 3em)[⇊ SEE NEXT PAGE ⇊]])
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#pagebreak()
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5. Calculate the value of each of these quantities (10 pts).
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#grid(
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columns: 3,
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align: center,
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gutter: 2em,
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[
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a. $P(7,2)$
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#solve[$7! / (7 - 2)! = 42$]
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],
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[
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b. $P(6,3)$
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#solve[$6! / (6 - 3)! = 120$]
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],
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[
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c. $P(12,9)$
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#solve[$12! / (12 - 9)! = 79,833,600$]
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],
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[
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d. $C(9,5)$
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#solve[$9! / (5! ⋅ (9 - 5)!) = 120$]
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],
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[
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f. $C(12,7)$
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#solve[$12! / (7! ⋅ (12 - 7)!) = 792$]
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],
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)
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6. How many ways are there to select a first-prize winner, a second-prize winner, and a third-prize winner from 180 different people who have entered a contest? (6 pts)
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#note[$180 ⋅ 179 ⋅ 178 = #solvein[5,735,160]$]
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7. How many bit strings of length 16 contain... (12 pts)
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#grid(
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columns: 2,
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align: center,
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gutter: 2em,
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[
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a. Exactly five 0s?
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#solve[$16! / (5! ⋅ (16 - 5)!) = 4,368$]
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],
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[
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b. At most five 0s?
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#note[
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$
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&C(16,0) &= &16! / (0! ⋅ (16 - 0)!)& &= &1\
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+ &C(16,1) &= &16! / (1! ⋅ (16 - 1)!)& &= &16\
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+ &C(16,2) &= &16! / (2! ⋅ (16 - 2)!)& &= &120\
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+ &C(16,3) &= &16! / (3! ⋅ (16 - 3)!)& &= &560\
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+ &C(16,4) &= &16! / (4! ⋅ (16 - 4)!)& &= &1,820\
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+ &C(16,5) &= &16! / (5! ⋅ (16 - 5)!)& &= &4,368\
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$
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#align(center)[#solve[$6,885$]]
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]
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],
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[
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c. At least five 0s?
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#note[
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$
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2^16 - 6,885 = #solvein[58,651]
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$
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]
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],
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[
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d. An equal number of 0s and 1s?
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#note[
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$
|
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C(16,8) = 16!/(8! ⋅ (16 - 8)!) = #solvein[12,870]
|
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$
|
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]
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],
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)
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#align(center + bottom, note[#text(size: 3em)[⇊ SEE NEXT PAGE ⇊]])
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#pagebreak()
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8. How many permutations of letters ${"A", "B", "C", "D", "E", "F", "G", "H", "I", "J"}$ contain (no letters repeated)... (12 pts)
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#grid(
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columns: 2,
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gutter: 1em,
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inset: (left: 2em, right: 2em),
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[
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a. The string AJ?
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#note[
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Our set is ${{"AJ"}, "B", "C", "D", "E", "F", "G", "H", "I"}$.
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Total of 9 permutations: $9! = #solvein[362,880]$
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]
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],
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[
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b. The string BIG?
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#note[
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Our set is ${{"BIG"}, "A", "C", "D", "E", "F", "H", "J"}$.
|
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|
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Total of 8 permutations: $8! = #solvein[40,320]$
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]
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],
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||||
[
|
||||
c. The strings AEG and DB?
|
||||
#note[
|
||||
Our set is ${{"AEG"}, {"DB"}, "C", "F", "H", "I", "J"}$.
|
||||
|
||||
Total of 7 permutations: $7! = #solvein[5,040]$
|
||||
]
|
||||
],
|
||||
[
|
||||
d. The strings BG, FC, and AE?
|
||||
#note[
|
||||
Our set is ${{"AE"}, {"BG"}, {"FC"}, "D", "H", "I", "J"}$.
|
||||
|
||||
Total of 7 permutations: $7! = #solvein[5,040]$
|
||||
]
|
||||
],
|
||||
|
||||
[
|
||||
e. The strings FIG and GIF?
|
||||
#note[
|
||||
FIG = GIF
|
||||
|
||||
Our set is ${"A", "B", "C", "D", "E", {"GIF"}, "H", "J"}$.
|
||||
|
||||
Total of 8 permutations: $8! = #solvein[40,320]$
|
||||
]
|
||||
],
|
||||
[
|
||||
f. The strings CD and DJ?
|
||||
#note[
|
||||
CD and DJ overlap, thus the string can be considered CDJ.
|
||||
|
||||
Our set is ${"A", "B", {"CDJ"}, "E", "F", "G", "H", "I"}$.
|
||||
|
||||
Total of 8 permutations: $8! = #solvein[40,320]$
|
||||
]
|
||||
],
|
||||
)
|
||||
|
||||
9. Suppose that a department contains 9 dentists and 15 optometrists. How many ways are there to form a committee with 7 members if it must have more dentists than optometrists? (8 pts)
|
||||
#note[
|
||||
$
|
||||
"1. 4 dentists and 3 optometrists" -> C(9,4) ⋅ C(15,3) &= 126 ⋅ 455 &=& 57,330\
|
||||
"2. 5 dentists and 2 optometrists" -> C(9,5) ⋅ C(15,2) &= 126 ⋅ 105 &=& 13,230\
|
||||
"3. 6 dentists and 1 optometrists" -> C(9,6) ⋅ C(15,1) &= 84 ⋅ 15 &=& 1,260\
|
||||
"4. 7 dentists and 0 optometrists" -> C(9,7) ⋅ C(15,0) &= 36 ⋅ 1 &=& 36\
|
||||
\
|
||||
\
|
||||
57,330 + 13,230 + 1,260 + 63 = #solvein[71,883]
|
||||
$
|
||||
]
|
||||
|
||||
#align(center + bottom, note[#text(size: 3em)[⇊ SEE NEXT PAGE ⇊]])
|
||||
#pagebreak()
|
||||
|
||||
10. What is the coefficient of $x^17 ⋅ y^14$ in $(2x - 3y)^31$? (You do not need to calculate the final value. Just write down the formula of the coefficient) (10 pts)
|
||||
|
||||
#note[
|
||||
$x = 2x, y = -3y, (X + Y)^31$
|
||||
$
|
||||
&= mat(31; 17) X^17 ⋅ Y^14\
|
||||
&= mat(31; 17) (2x)^17 ⋅ (-3y)^14\
|
||||
&= mat(31; 17) (2)^17 ⋅ (-3)^14 x^17 ⋅ y^13\
|
||||
&= #solve[$-mat(31; 17) 2^17 ⋅ 3^14$]
|
||||
$
|
||||
]
|
Loading…
Reference in New Issue
Block a user