#set page(margin: (x: .5in, y: .5in)) #let solve(solution) = [ #let solution = align( center, block( inset: 5pt, stroke: blue + .3pt, fill: rgb(0, 149, 255, 15%), radius: 4pt, )[#align(left)[#solution]], ) #solution ] #align(center)[ = CS 3333 Mathematical Foundations Homework 1 (100 points)\ #underline[Price Hiller] *|* #underline[zfp106] ] *Submission:* + Submit a single PDF (not Word) file through Canvas. + You can either edit the Word file directly or write down your solution in any other text document using other editors. + Convert the Word document or the text document into a single PDF file. + If there is any plagiarism, you will lose all points on the questions at first time. In next, you will lose all points in the whole homework. #line(length: 100%, stroke: .25pt) *Questions:* 1. Does 41 divide each of these numbers (just answer yes or no)? (16 points) #solve[#align(center)[]#grid( columns: (100pt, 100pt), rows: (10pt, auto), gutter: 3pt, [a) 123 *(yes)*], [b) 92 *(no)*], [c) 413 *(no)*], [d) 1640 *(yes)*], )] 2. Prove/Show that if $a | b$ and $b | a$, where $a$ and $b$ are integers, then $a = b$ or $a = -b$. (20 points) #solve[ + $b = a k$, where $k$ is an integer + $a = b q$, where $q$ is an integer + Use $a = b q$ + Substitute $b$: $a = a k q$ + Algebra: $k q = 1$ + ∵ $k$ & $q$ are integers, $k$ and $q$ must be $1$ or $-1$ + ∴ $a = b$ or $a = -b$ ] 3. Prove that if $a$, $b$, $c$, and $d$ are integers, where $a ≠ 0$ and $b ≠ 0$, such that $a | c$ and $b | d$, then $a b | c d$. (20 points) #solve[ + $c = k a$, where $k$ is an integer + $d = q b$, where $q$ is an integer + $c d = (k a)(q b) = (k q)(a b)$ + $a b | (k q)(a b)$ is true + ∴ $a b | c d$ ] 4. When $x$ is an integer, prove that $1 + x^2 <= (1 + x)^2$ is true or disprove it by providing a counterexample. (20 points) #solve[ + False. Counterexample: let $x = -1$ + Substitute $x$: $1 + (-1)^2 <= (1 + (-1))^2$ + Solve: $2 <= 0$, not true + ∴ when $x$ is an integer $1 + x^2 <= (1 + x)^2$ is false ] 5. Prove that if $a$ is an integer that is not divisible by $3$, denoted as $3 ∤ a$, then $(a + 1)(a + 2)$ is divisible by $3$, denoted as $3 | (a + 1)(a + 2)$. (24 points) #solve[ + Prove: $3 | (a + 1)(a + 2)$ + Assume $a = 3k + 1$, where $k$ is an integer + Substitute $a$: $((3k + 1) + 1)((3k + 1) + 2)$ + Algebra: $9k^2 + 15k + 6$ + Factor $3$: $3(3k^2 + 5k + 2)$ + $3$ times some integer is necessarily divisible by $3$ according to divisibility + ∴ If $3 ∤ a$, then $3 | (a + 1)(a + 2)$ ]